What Is The Output Of The Code Below? Class Test { Public Static Void Main(String[] Args) { Teacher YourTA = New TeachingAssistant(); YourTA.grade(); YourTA.officeHour(); } } Abstract Class Teacher { Public Teacher() { System.out.println("New Teacher Created"); } Abstract Void Grade(); Void OfficeHour() { System.out.println("Office Hours"); } } Class TeachingAssistant Extends Teacher { @Override Void Grade() { System.out.println("Grade Your Hw7 Now"); } } » Re⥃askly

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What is the output of the code below?

class Test { 
    public static void main(String[] args) { 
        Teacher yourTA = new TeachingAssistant(); 
        yourTA.grade(); 
        yourTA.officeHour(); 
    }
} 

abstract class Teacher { 
    public Teacher() { 
        System.out.println("New Teacher created"); 
    }
    abstract void grade(); 
    void officeHour() { 
        System.out.println("Office Hours"); 
    }
}

class TeachingAssistant extends Teacher {
    @Override
    void grade() { 
        System.out.println("Grade your hw7 now"); 
    }
}

Home » What is the output of the code below? class Test { public static void main(String[] args) { Teacher yourTA = new TeachingAssistant(); yourTA.grade(); yourTA.officeHour(); } } abstract class Teacher { public Teacher() { System.out.println(“New Teacher created”); } abstract void grade(); void officeHour() { System.out.println(“Office Hours”); } } class TeachingAssistant extends Teacher { @Override void grade() { System.out.println(“Grade your hw7 now”); } }

Practice More Questions From: Quiz 4 : More with Abstract Classes & Debugging

Q:

What is the output of the code below? abstract class Beverage { abstract void pour(); } class Tea extends Beverage { @Override void pour() { System.out.println(“Pouring Tea”); } } class Coffee extends Beverage { @Override void pour() { System.out.println(“Pouring Coffee”); } } class Test { public static void main(String[] args) { Beverage tea = new Coffee(); tea.pour(); } }

Q:

What is the output of the code below if we change the first line in the main function to be: Beverage bev = new Beverage(); abstract class Beverage { abstract void pour(); } class Tea extends Beverage { @Override void pour() { System.out.println(“Pouring Tea”); } } class Coffee extends Beverage { @Override void pour(){ System.out.println(“Pouring Coffee”); } } class Test { public static void main(String[] args) { Beverage tea = new Coffee(); tea.pour(); } }

Q:

What is the output of the code below? class Test { public static void main(String[] args) { Teacher yourTA = new TeachingAssistant(); yourTA.grade(); yourTA.officeHour(); } } abstract class Teacher { public Teacher() { System.out.println(“New Teacher created”); } abstract void grade(); void officeHour() { System.out.println(“Office Hours”); } } class TeachingAssistant extends Teacher { @Override void grade() { System.out.println(“Grade your hw7 now”); } }

Q:

What’s the result of the following code? abstract class Base { void fun() { System.out.println(“Base fun() called”); } } class Derived extends Base {} class Main { public static void main(String args[]) { Base b = new Derived(); b.fun(); } }

Q:

What’s the result of the following code? abstract class Base { void fun() { System.out.println(“Base fun() called”); } } class Derived extends Base { @Override void fun() { System.out.println(“Fun overwritten!”); } } class Main { public static void main(String args[]) { Base b = new Derived(); b.fun(); } }

Q:

How can we stop execution of a program, and move from one desired step to another?

Q:

Which of the following allows us to deep dive into the execution of a method call, from within another method?

Q:

When using Eclipse’s debugger, which button will you click if you want to go back to the caller of the current method?

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